* We now know we have on the order of 2^len objects, which
* expects a collision at 2^(len/2). But we also care about hex
* chars, not bits, and there are 4 bits per hex. So all
- * together we need to divide by 2; but we also want to round
- * odd numbers up, hence adding one before dividing.
+ * together we need to divide by 2 and round up.
*/
- len = (len + 1) / 2;
+ len = DIV_ROUND_UP(len, 2);
/*
* For very small repos, we stick with our regular fallback.
*/