+#include <stdlib.h>
#include "cache.h"
-#include "revision.h"
+#include "commit.h"
-/*
- * This is stupid. We could have much better heurstics, I bet.
- */
-static int better(struct revision *new, struct revision *old)
+#define PARENT1 1
+#define PARENT2 2
+#define UNINTERESTING 4
+
+static struct commit *interesting(struct commit_list *list)
{
- return new->date > old->date;
+ while (list) {
+ struct commit *commit = list->item;
+ list = list->next;
+ if (commit->object.flags & UNINTERESTING)
+ continue;
+ return commit;
+ }
+ return NULL;
}
-static struct revision *common_parent(struct revision *rev1, struct revision *rev2)
+/*
+ * A pathological example of how this thing works.
+ *
+ * Suppose we had this commit graph, where chronologically
+ * the timestamp on the commit are A <= B <= C <= D <= E <= F
+ * and we are trying to figure out the merge base for E and F
+ * commits.
+ *
+ * F
+ * / \
+ * E A D
+ * \ / /
+ * B /
+ * \ /
+ * C
+ *
+ * First we push E and F to list to be processed. E gets bit 1
+ * and F gets bit 2. The list becomes:
+ *
+ * list=F(2) E(1), result=empty
+ *
+ * Then we pop F, the newest commit, from the list. Its flag is 2.
+ * We scan its parents, mark them reachable from the side that F is
+ * reachable from, and push them to the list:
+ *
+ * list=E(1) D(2) A(2), result=empty
+ *
+ * Next pop E and do the same.
+ *
+ * list=D(2) B(1) A(2), result=empty
+ *
+ * Next pop D and do the same.
+ *
+ * list=C(2) B(1) A(2), result=empty
+ *
+ * Next pop C and do the same.
+ *
+ * list=B(1) A(2), result=empty
+ *
+ * Now it is B's turn. We mark its parent, C, reachable from B's side,
+ * and push it to the list:
+ *
+ * list=C(3) A(2), result=empty
+ *
+ * Now pop C and notice it has flags==3. It is placed on the result list,
+ * and the list now contains:
+ *
+ * list=A(2), result=C(3)
+ *
+ * We pop A and do the same.
+ *
+ * list=B(3), result=C(3)
+ *
+ * Next, we pop B and something very interesting happens. It has flags==3
+ * so it is also placed on the result list, and its parents are marked
+ * uninteresting, retroactively, and placed back on the list:
+ *
+ * list=C(7), result=C(7) B(3)
+ *
+ * Now, list does not have any interesting commit. So we find the newest
+ * commit from the result list that is not marked uninteresting. Which is
+ * commit B.
+ */
+
+static int show_all = 0;
+
+static int merge_base(struct commit *rev1, struct commit *rev2)
{
- int i;
- struct revision *best = NULL;
-
- mark_reachable(rev1, 1);
- mark_reachable(rev2, 2);
- for (i = 0; i < nr_revs ;i++) {
- struct revision *rev = revs[i];
- if ((rev->flags & 3) != 3)
- continue;
- if (!best) {
- best = rev;
- continue;
+ struct commit_list *list = NULL;
+ struct commit_list *result = NULL;
+
+ if (rev1 == rev2) {
+ printf("%s\n", sha1_to_hex(rev1->object.sha1));
+ return 0;
+ }
+
+ parse_commit(rev1);
+ parse_commit(rev2);
+
+ rev1->object.flags |= 1;
+ rev2->object.flags |= 2;
+ insert_by_date(rev1, &list);
+ insert_by_date(rev2, &list);
+
+ while (interesting(list)) {
+ struct commit *commit = list->item;
+ struct commit_list *tmp = list, *parents;
+ int flags = commit->object.flags & 7;
+
+ list = list->next;
+ free(tmp);
+ if (flags == 3) {
+ insert_by_date(commit, &result);
+
+ /* Mark parents of a found merge uninteresting */
+ flags |= UNINTERESTING;
}
- if (better(rev, best))
- best = rev;
+ parents = commit->parents;
+ while (parents) {
+ struct commit *p = parents->item;
+ parents = parents->next;
+ if ((p->object.flags & flags) == flags)
+ continue;
+ parse_commit(p);
+ p->object.flags |= flags;
+ insert_by_date(p, &list);
+ }
+ }
+
+ if (!result)
+ return 1;
+
+ while (result) {
+ struct commit *commit = result->item;
+ result = result->next;
+ if (commit->object.flags & UNINTERESTING)
+ continue;
+ printf("%s\n", sha1_to_hex(commit->object.sha1));
+ if (!show_all)
+ return 0;
+ commit->object.flags |= UNINTERESTING;
}
- return best;
+ return 0;
}
+static const char merge_base_usage[] =
+"git-merge-base [--all] <commit-id> <commit-id>";
+
int main(int argc, char **argv)
{
- unsigned char rev1[20], rev2[20];
- struct revision *common;
-
- if (argc != 3 || get_sha1_hex(argv[1], rev1) || get_sha1_hex(argv[2], rev2))
- usage("merge-base <commit1> <commit2>");
-
- /*
- * We will eventually want to include a revision cache file
- * that "rev-tree.c" has generated, since this is going to
- * otherwise be quite expensive for big trees..
- *
- * That's some time off, though, and in the meantime we know
- * that we have a solution to the eventual expense.
- */
- common = common_parent(parse_commit(rev1), parse_commit(rev2));
- if (!common)
- die("no common parent found");
- printf("%s\n", sha1_to_hex(common->sha1));
- return 0;
+ struct commit *rev1, *rev2;
+ unsigned char rev1key[20], rev2key[20];
+
+ while (1 < argc && argv[1][0] == '-') {
+ char *arg = argv[1];
+ if (!strcmp(arg, "-a") || !strcmp(arg, "--all"))
+ show_all = 1;
+ else
+ usage(merge_base_usage);
+ argc--; argv++;
+ }
+ if (argc != 3 ||
+ get_sha1(argv[1], rev1key) ||
+ get_sha1(argv[2], rev2key))
+ usage(merge_base_usage);
+ rev1 = lookup_commit_reference(rev1key);
+ rev2 = lookup_commit_reference(rev2key);
+ if (!rev1 || !rev2)
+ return 1;
+ return merge_base(rev1, rev2);
}