To find stationary points of a function, substitute $x$ value of given point into derivative. Solve for ${dy \over dx}=0$. Integrate to find original function.
-## Kinematics
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-$${dV \over dt} = {\operatorname{change in volume} \over \operatorname{respect to time}}$$
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-**position $x$** - distance from origin or fixed point
-**displacement $s$** - change in position from starting point (vector)
-**velocity $v$** - change in position with respect to time
-**acceleration $a$** - change in velocity
-**speed** - magnitude of velocity
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-$$v_{\operatorname{avg}}={\Delta x \over \Delta t}={{x_2 - x_1} \over {t_2 - t_1}}$$
-$$\operatorname{speed}_{\operatorname{avg}}={\Delta v \over \Delta t}$$
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