[spec] typo in segment area formula
[notes.git] / spec / spec-collated.tex
index 39ab74ecb586908cb18c2851ac08382cc756a136..989f7707f20cb52a2481797b2c25d6b66c004b41 100644 (file)
 \documentclass[a4paper]{article}
-\usepackage[a4paper,margin=2cm]{geometry}
-\usepackage{multicol}
-\usepackage{multirow}
+\usepackage[dvipsnames, table]{xcolor}
+\usepackage{adjustbox}
 \usepackage{amsmath}
 \usepackage{amssymb}
-\usepackage{harpoon}
-\usepackage{tabularx}
-\usepackage{makecell}
-\usepackage[dvipsnames, table]{xcolor}
+\usepackage{array}
 \usepackage{blindtext}
+\usepackage{dblfloatfix}
+\usepackage{enumitem}
+\usepackage{fancyhdr}
+\usepackage[a4paper,margin=1.8cm]{geometry}
 \usepackage{graphicx}
-\usepackage{wrapfig}
-\usepackage{tikz}
-\usepackage{tikz-3dplot}
+\usepackage{harpoon}
+\usepackage{hhline}
+\usepackage{import}
+\usepackage{keystroke}
+\usepackage{listings}
+\usepackage{makecell}
+\usepackage{mathtools}
+\usepackage{mathtools}
+\usepackage{multicol}
+\usepackage{multirow}
 \usepackage{pgfplots}
-\usetikzlibrary{calc}
-\usetikzlibrary{angles}
-\usetikzlibrary{datavisualization.formats.functions}
-\usetikzlibrary{decorations.markings}
+\usepackage{pst-plot}
+\usepackage{rotating}
+%\usepackage{showframe} % debugging only
+\usepackage{subfiles}
+\usepackage{tabularx}
+\usepackage{tcolorbox}
+\usepackage{tikz-3dplot}
+\usepackage{tikz}
+\usepackage{tkz-fct}
+\usepackage[obeyspaces]{url}
+\usepackage{wrapfig}
+
+
+\usetikzlibrary{%
+  angles,
+  arrows,
+  arrows.meta,
+  calc,
+  datavisualization.formats.functions,
+  decorations,
+  decorations.markings,
+  decorations.text,
+  decorations.pathreplacing,
+  decorations.text,
+  scopes
+}
+
+\newcommand\given[1][]{\:#1\vert\:}
+\newcommand{\midarrow}{\tikz \draw[-triangle 90] (0,0) -- +(.1,0);}
+
 \usepgflibrary{arrows.meta}
-\usepackage{fancyhdr}
+\pgfplotsset{compat=1.16}
+\pgfplotsset{every axis/.append style={
+  axis x line=middle,
+  axis y line=middle,
+  axis line style={->},
+  xlabel={$x$},
+  ylabel={$y$},
+}}
+
+\psset{dimen=monkey,fillstyle=solid,opacity=.5}
+\def\object{%
+    \psframe[linestyle=none,fillcolor=blue](-2,-1)(2,1)
+    \psaxes[linecolor=gray,labels=none,ticks=none]{->}(0,0)(-3,-3)(3,2)[$x$,0][$y$,90]
+    \rput{*0}{%
+        \psline{->}(0,-2)%
+        \uput[-90]{*0}(0,-2){$\vec{w}$}}
+}
+
 \pagestyle{fancy}
+\fancypagestyle{plain}{\fancyhead[LO,LE]{} \fancyhead[CO,CE]{}} % rm title & author for first page
 \fancyhead[LO,LE]{Year 12 Specialist}
 \fancyhead[CO,CE]{Andrew Lorimer}
 
-\usepackage{mathtools}
-\usepackage{xcolor} % used only to show the phantomed stuff
 \renewcommand\hphantom[1]{{\color[gray]{.6}#1}} % comment out!
-\setlength\fboxsep{0pt} \setlength\fboxrule{.2pt} % for the \fboxes
 \newcommand*\leftlap[3][\,]{#1\hphantom{#2}\mathllap{#3}}
 \newcommand*\rightlap[2]{\mathrlap{#2}\hphantom{#1}}
+\linespread{1.5}
+\setlength{\parindent}{0pt}
+\setlength\fboxsep{0pt} \setlength\fboxrule{.2pt} % for the \fboxes
+
 \newcolumntype{L}[1]{>{\hsize=#1\hsize\raggedright\arraybackslash}X}%
 \newcolumntype{R}[1]{>{\hsize=#1\hsize\raggedleft\arraybackslash}X}%
-\definecolor{cas}{HTML}{e6f0fe}
-\linespread{1.5}
-\newcommand{\midarrow}{\tikz \draw[-triangle 90] (0,0) -- +(.1,0);}
+\newcolumntype{Y}{>{\centering\arraybackslash}X}
+
+\definecolor{cas}{HTML}{cde1fd}
+\definecolor{important}{HTML}{fc9871}
+\definecolor{dark-gray}{gray}{0.2}
+\definecolor{light-gray}{HTML}{cccccc}
+\definecolor{peach}{HTML}{e6beb2}
+\definecolor{lblue}{HTML}{e5e9f0}
+
 \newcommand{\tg}{\mathop{\mathrm{tg}}}
 \newcommand{\cotg}{\mathop{\mathrm{cotg}}}
 \newcommand{\arctg}{\mathop{\mathrm{arctg}}}
 \newcommand{\arccotg}{\mathop{\mathrm{arccotg}}}
 
+\newtcolorbox{cas}{colframe=cas!75!black, fonttitle=\sffamily\bfseries, title=On CAS, left*=3mm}
+\newtcolorbox{theorembox}[1]{colback=green!10!white, colframe=blue!20!white, coltitle=black, fontupper=\sffamily, fonttitle=\sffamily, #1}
+\newtcolorbox{warning}{colback=white!90!black, leftrule=3mm, colframe=important, coltext=darkgray, fontupper=\sffamily\bfseries}
 
-                  \pgfplotsset{every axis/.append style={
-                    axis x line=middle,    % put the x axis in the middle
-                    axis y line=middle,    % put the y axis in the middle
-                    axis line style={->}, % arrows on the axis
-                    xlabel={$x$},          % default put x on x-axis
-                    ylabel={$y$},          % default put y on y-axis
-                  }}
 \begin{document}
 
+\title{\vspace{-22mm}Year 12 Specialist\vspace{-4mm}}
+\author{Andrew Lorimer}
+\date{}
+\maketitle
+\vspace{-9mm}
 \begin{multicols}{2}
 
   \section{Complex numbers}
 
   \[\mathbb{C}=\{a+bi:a,b\in\mathbb{R}\}\]
-
   \begin{align*}
     \text{Cartesian form: } & a+bi\\
     \text{Polar form: } & r\operatorname{cis}\theta
 
   \subsection*{Operations}
 
-  \definecolor{shade1}{HTML}{ffffff}
-  \definecolor{shade2}{HTML}{e6f2ff}
-  \definecolor{shade3}{HTML}{cce2ff}
-  \begin{tabularx}{\columnwidth}{r|X|X}
+  \begin{tabularx}{\columnwidth}{|r|X|X|}
+    \hline
+    \rowcolor{cas}
     & \textbf{Cartesian} & \textbf{Polar} \\
     \hline
     \(z_1 \pm z_2\) & \((a \pm c)(b \pm d)i\) & convert to \(a+bi\)\\
     \hline
     \(z_1 \cdot z_2\) & \(ac-bd+(ad+bc)i\) & \(r_1r_2 \operatorname{cis}(\theta_1 + \theta_2)\)\\
     \hline
-    \(z_1 \div z_2\) & \((z_1 \overline{z_2}) \div |z_2|^2\) & \(\left(\frac{r_1}{r_2}\right) \operatorname{cis}(\theta_1 - \theta_2)\)
+    \(z_1 \div z_2\) & \((z_1 \overline{z_2}) \div |z_2|^2\) & \(\left(\frac{r_1}{r_2}\right) \operatorname{cis}(\theta_1 - \theta_2)\) \\
+    \hline
   \end{tabularx}
 
   \subsubsection*{Scalar multiplication in polar form}
   \[k\left(r \operatorname{cis}\theta\right)=kr \operatorname{cis}\left(\begin{cases}\theta - \pi & |0<\operatorname{Arg}(z)\le \pi \\ \theta + \pi & |-\pi<\operatorname{Arg}(z)\le 0\end{cases}\right)\]
 
     \subsection*{Conjugate}
-
+    \vspace{-7mm} \hfill  \colorbox{cas}{\texttt{conjg(a+bi)}}
     \begin{align*}
       \overline{z} &= a \mp bi\\
       &= r \operatorname{cis}(-\theta)
     \end{align*}
 
-    \noindent \colorbox{cas}{On CAS: \texttt{conjg(a+bi)}}
-
     \subsubsection*{Properties}
 
     \begin{align*}
       \overline{z_1 \pm z_2} &= \overline{z_1}\pm\overline{z_2}\\
       \overline{z_1 \cdot z_2} &= \overline{z_1}\cdot\overline{z_2}\\
-      \overline{kz} &= k\overline{z} \quad | \quad k \in \mathbb{R}\\
+      \overline{kz} &= k\overline{z} \> \forall \>  k \in \mathbb{R}\\
       z\overline{z} &= (a+bi)(a-bi)\\
       &= a^2 + b^2\\
       &= |z|^2
       \frac{z_1}{z_2}&=z_1z_2^{-1}\\
       &=\frac{z_1\overline{z_2}}{|z_2|^2}\\
       &=\frac{(a+bi)(c-di)}{c^2+d^2}\\
-      & \qquad \text{(rationalise denominator)}
+      & \text{then rationalise denominator}
     \end{align*}
 
     \subsection*{Polar form}
 
-    \begin{align*}
-      z&=r\operatorname{cis}\theta\\
-      &=r(\cos \theta + i \sin \theta)
-    \end{align*}
+    \[ r \operatorname{cis} \theta = r\left( \cos \theta + i \sin \theta \right) \]
 
     \begin{itemize}
       \item{\(r=|z|=\sqrt{\operatorname{Re}(z)^2 + \operatorname{Im}(z)^2}\)}
-      \item{\(\theta = \operatorname{arg}(z)\) \quad \colorbox{cas}{On CAS: \texttt{arg(a+bi)}}}
+      \item{\(\theta = \operatorname{arg}(z)\) \hfill \colorbox{cas}{\texttt{arg(a+bi)}}}
       \item{\(\operatorname{Arg}(z) \in (-\pi,\pi)\) \quad \bf{(principal argument)}}
-      \item{\colorbox{cas}{Convert on CAS:}\\ \verb|compToTrig(a+bi)| \(\iff\) \verb|cExpand{r·cisX}|}
       \item{Multiple representations:\\\(r\operatorname{cis}\theta=r\operatorname{cis}(\theta+2n\pi)\) with \(n \in \mathbb{Z}\) revolutions}
       \item{\(\operatorname{cis}\pi=-1,\qquad \operatorname{cis}0=1\)}
     \end{itemize}
 
+    \begin{cas}
+      \-\hspace{1em}\verb|compToTrig(a+bi)| \(\iff\) \verb|cExpand{r·cisX}|
+    \end{cas}
+
     \subsection*{de Moivres' theorem}
 
-    \[(r \operatorname{cis} \theta)^n = r^n \operatorname{cis}(n\theta) \text{ where } n \in \mathbb{Z}\]
+    \begin{theorembox}{}
+      \[(r \operatorname{cis} \theta)^n = r^n \operatorname{cis}(n\theta) \text{ where } n \in \mathbb{Z}\]
+    \end{theorembox}
 
     \subsection*{Complex polynomials}
 
       \hline
     \end{tabularx}
 
+    \begin{theorembox}{title=Factor theorem}
+      If \(\beta z + \alpha\) is a factor of \(P(z)\), \\
+      \-\hspace{1em}then \(P(-\dfrac{\alpha}{\beta})=0\).
+    \end{theorembox}
+
     \subsection*{\(n\)th roots}
 
     \(n\)th roots of \(z=r\operatorname{cis}\theta\) are:
                   \begin{tikzpicture}
                     \begin{axis}[yticklabel style={yshift=1.0pt, anchor=north east},x=0.1cm, y=1cm, ymax=2, ymin=-2, xticklabels={}, ytick={-1.5708,1.5708},yticklabels={\(-\frac{\pi}{2}\),\(\frac{\pi}{2}\)}]
                       \addplot[color=orange, smooth] gnuplot [domain=-35:35, unbounded coords=jump,samples=350] {atan(x)} node [pos=0.5, above left] {\(\tan^{-1}x\)};
-                      \addplot[->, gray, dotted, thick, domain=-35:35] {1.5708};
-                      \addplot[->, gray, dotted, thick, domain=-35:35] {-1.5708};
+                      \addplot[gray, dotted, thick, domain=-35:35] {1.5708} node [black, font=\footnotesize, below right, pos=0] {\(y=\frac{\pi}{2}\)};
+                      \addplot[gray, dotted, thick, domain=-35:35] {-1.5708} node [black, font=\footnotesize, above left, pos=1] {\(y=-\frac{\pi}{2}\)};
                     \end{axis}
                   \end{tikzpicture}
-\columnbreak
+
+                  \subsection*{Mensuration}
+
+                  \begin{tikzpicture}[draw=blue!70,thick]
+                    \filldraw[fill=lblue] circle (2cm);
+                    \filldraw[fill=white] 
+                    (320:2cm) node[right] {} 
+                    -- (220:2cm) node[left] {} 
+                    arc[start angle=220, end angle=320, radius=2cm] 
+                    -- cycle;
+                    \node {Major Segment};
+                    \node at (-90:2) {Minor Segment};
+
+                    \begin{scope}[xshift=4.5cm]
+                      \draw circle (2cm);
+                      \filldraw[fill=lblue] 
+                      (320:2cm) node[right] {}
+                      -- (0,0) node[above] {}
+                      -- (220:2cm) node[left] {} 
+                      arc[start angle=220, end angle=320, radius=2cm]
+                      -- cycle;
+                      \node at (90:1cm) {Major Sector};
+                      \node at (-90:1.5) {Minor Sector};
+                    \end{scope}
+                  \end{tikzpicture}
+
+
+                  \begin{align*}
+                    \textbf{Sectors: } A &= \pi r^2 \dfrac{\theta}{2\pi} \\
+                    &= \dfrac{r^2 \theta}{2}
+                  \end{align*}
+
+                  \[ \textbf{Segments: } A = \dfrac{r^2}{2} \left(\theta - \sin \theta \right) \]
+
+                  \begin{align*}
+                    \textbf{Chords: } \operatorname{crd} \theta &= \sqrt{(1 - \cos\theta)^2 + \sin^2 \theta} \\
+                    &= \sqrt{2 - 2\cos\theta} \\
+                    &= 2 \sin \left(\dfrac{\theta}{2}\right)
+                  \end{align*}
+
                   \section{Differential calculus}
 
+                  \[f^\prime(x) = \lim_{\delta x \rightarrow 0}{\delta y \over \delta x}={\frac{dy}{dx}}\]
+
                   \subsection*{Limits}
 
                   \[\lim_{x \rightarrow a}f(x)\]
                       \(f(x)\) is continuous \(\iff L^-=L^+=f(x) \> \forall x\)
                   \end{enumerate}
 
-                  \subsection*{Gradients of secants and tangents}
+                  \subsection*{Gradients}
 
                   \textbf{Secant (chord)} - line joining two points on curve\\
                   \textbf{Tangent} - line that intersects curve at one point
 
-                  \subsection*{First principles derivative}
+                  \subsubsection*{Points of Inflection}
 
-                  \[f^\prime(x) = \lim_{\delta x \rightarrow 0}{\delta y \over \delta x}={\frac{dy}{dx}}\]
+                  \emph{Stationary point} - i.e.
+                  \(f^\prime(x)=0\)\\
+                  \emph{Point of inflection} - max \(|\)gradient\(|\) (i.e.
+                  \(f^{\prime\prime} = 0\))
 
-                  \subsubsection*{Logarithmic identities}
-
-                  \(\log_b (xy)=\log_b x + \log_b y\)\\
-                  \(\log_b x^n = n \log_b x\)\\
-                  \(\log_b y^{x^n} = x^n \log_b y\)
-
-                  \subsubsection*{Index identities}
-
-                  \(b^{m+n}=b^m \cdot b^n\)\\
-                  \((b^m)^n=b^{m \cdot n}\)\\
-                  \((b \cdot c)^n = b^n \cdot c^n\)\\
-                  \({a^m \div a^n} = {a^{m-n}}\)
-
-                  \subsection*{Derivative rules}
-
-                  \renewcommand{\arraystretch}{1.4}
-                  \begin{tabularx}{\columnwidth}{rX}
-                    \hline
-                    \(f(x)\) & \(f^\prime(x)\)\\
-                    \hline
-                    \(\sin x\) & \(\cos x\)\\
-                    \(\sin ax\) & \(a\cos ax\)\\
-                    \(\cos x\) & \(-\sin x\)\\
-                    \(\cos ax\) & \(-a \sin ax\)\\
-                    \(\tan f(x)\) & \(f^2(x) \sec^2f(x)\)\\
-                    \(e^x\) & \(e^x\)\\
-                    \(e^{ax}\) & \(ae^{ax}\)\\
-                    \(ax^{nx}\) & \(an \cdot e^{nx}\)\\
-                    \(\log_e x\) & \(\dfrac{1}{x}\)\\
-                    \(\log_e {ax}\) & \(\dfrac{1}{x}\)\\
-                    \(\log_e f(x)\) & \(\dfrac{f^\prime (x)}{f(x)}\)\\
-                    \(\sin(f(x))\) & \(f^\prime(x) \cdot \cos(f(x))\)\\
-                    \(\sin^{-1} x\) & \(\dfrac{1}{\sqrt{1-x^2}}\)\\
-                    \(\cos^{-1} x\) & \(\dfrac{-1}{sqrt{1-x^2}}\)\\
-                    \(\tan^{-1} x\) & \(\dfrac{1}{1 + x^2}\)\\
-                    \(\frac{d}{dy}f(y)\) & \(\dfrac{1}{\frac{dx}{dy}}\) (reciprocal)\\
-                    \(uv\) & \(u \frac{dv}{dx}+v\frac{du}{dx} (product rule)\)\\
-                    \(\dfrac{u}{v}\) & \(\dfrac{v\frac{du}{dx}-u\frac{dv}{dx}}{v^2}\) (quotient rule)\\
-                    \(f(g(x))\) & \(f^\prime(g(x))\cdot g^\prime(x)\)\\
-                    \hline
-                  \end{tabularx}
+                  \subsubsection*{Strictly increasing/decreasing}
 
-                  \subsection*{Reciprocal derivatives}
+                  For \(x_2\) and \(x_1\) where \(x_2 > x_1\):
 
-                  \[\frac{1}{\frac{dy}{dx}} = \frac{dx}{dy}\]
+                  \textbf{strictly increasing}\\
+                  \-\hspace{1em}where \(f(x_2) > f(x_1)\) or \(f^\prime(x)>0\)
+
+                  \textbf{strictly decreasing}\\
+                  \hspace{1em}where \(f(x_2) < f(x_1)\) or \(f^\prime(x)<0\)
+                  \begin{warning}
+                    Endpoints are included, even where \(\boldsymbol{\frac{dy}{dx}=0}\)
+                  \end{warning}
 
-                  \subsection*{Differentiating \(x=f(y)\)}
-                  \begin{align*}
-                    \text{Find }& \frac{dx}{dy}\\
-                    \text{Then, }\frac{dx}{dy} &= \frac{1}{\frac{dy}{dx}} \\
-                    \implies {\frac{dy}{dx}} &= \frac{1}{\frac{dx}{dy}}\\
-                    \therefore {\frac{dy}{dx}} &= \frac{1}{\frac{dx}{dy}}
-                  \end{align*}
 
                   \subsection*{Second derivative}
                   \begin{align*}f(x) \longrightarrow &f^\prime (x) \longrightarrow f^{\prime\prime}(x)\\
 
                   \noindent Order of polynomial \(n\)th derivative decrements each time the derivative is taken
 
-                  \subsubsection*{Points of Inflection}
-
-                  \emph{Stationary point} - i.e.
-                  \(f^\prime(x)=0\)\\
-                  \emph{Point of inflection} - max \(|\)gradient\(|\) (i.e.
-                  \(f^{\prime\prime} = 0\))
 
+                  \subsection*{Slope fields}
+
+                  \begin{tikzpicture}[declare function={diff(\x,\y) = \x+\y;}]
+                    \begin{axis}[axis equal, ymin=-4, ymax=4, xmin=-4, xmax=4, ticks=none, enlargelimits=true, ]
+                      \addplot[thick, orange, domain=-4:2] {e^(x)-x-1};
+                      \pgfplotsinvokeforeach{-4,...,4}{%
+                        \draw[gray] ( {#1 -0.1}, {4 - diff(#1, 4) *0.1}) --  ( {#1 +0.1}, {4  + diff(#1, 4) *0.1});
+                        \draw[gray] ( {#1 -0.1}, {3 - diff(#1, 3) *0.1}) --  ( {#1 +0.1}, {3  + diff(#1, 3) *0.1});
+                        \draw[gray] ( {#1 -0.1}, {2 - diff(#1, 2) *0.1}) --  ( {#1 +0.1}, {2  + diff(#1, 2) *0.1});
+                        \draw[gray] ( {#1 -0.1}, {1 - diff(#1, 1) *0.1}) --  ( {#1 +0.1}, {1  + diff(#1, 1) *0.1});
+                        \draw[gray] ( {#1 -0.1}, {0 - diff(#1, 0) *0.1}) --  ( {#1 +0.1}, {0  + diff(#1, 0) *0.1});
+                        \draw[gray] ( {#1 -0.1}, {-1 - diff(#1, -1) *0.1}) --  ( {#1 +0.1}, {-1  + diff(#1, -1) *0.1});
+                        \draw[gray] ( {#1 -0.1}, {-2 - diff(#1, -2) *0.1}) --  ( {#1 +0.1}, {-2  + diff(#1, -2) *0.1});
+                        \draw[gray] ( {#1 -0.1}, {-3 - diff(#1, -3) *0.1}) --  ( {#1 +0.1}, {-3  + diff(#1, -3) *0.1});
+                        \draw[gray] ( {#1 -0.1}, {-4 - diff(#1, -4) *0.1}) --  ( {#1 +0.1}, {-4  + diff(#1, -4) *0.1});
+                      }
+                    \end{axis}
+                  \end{tikzpicture}
 
-                  \pgfplotsset{every axis/.append style={
-                    axis x line=none,    % put the x axis in the middle
-                    axis y line=none,    % put the y axis in the middle
-                  }}
                   \begin{table*}[ht]
                     \centering
-                    \begin{tabularx}{\textwidth}{rXXX}
+                    \begin{tabularx}{\textwidth}{|r|Y|Y|Y|}
                       \hline
-                      \rowcolor{shade2}
-                      & \centering\(\dfrac{d^2 y}{dx^2} > 0\)  & \centering \(\dfrac{d^2y}{dx^2}<0\) & \(\dfrac{d^2y}{dx^2}=0\) (inflection) \\
+                      \rowcolor{lblue}
+                      & \adjustbox{margin=0 1ex, valign=m}{\centering\(\dfrac{d^2 y}{dx^2} > 0\)}  & \adjustbox{margin=0 1ex, valign=m}{\centering \(\dfrac{d^2y}{dx^2}<0\)} & \adjustbox{margin=0 1ex, valign=m}{\(\dfrac{d^2y}{dx^2}=0\) (inflection)} \\
                       \hline
-                      \(\frac{dy}{dx}>0\) &
-                      \makecell{\\\begin{tikzpicture}\begin{axis}[xmin=-3,  xmax=0.8, scale=0.2, samples=50, unbounded coords=jump] \addplot[blue] {(e^(x))};  \addplot[red] {x/2.5+0.75}; \end{axis}\end{tikzpicture} \\Rising (concave up)}&
-                        \makecell{\\\begin{tikzpicture}\begin{axis}[xmin=0.1, xmax=4,   scale=0.2, samples=50, unbounded coords=jump] \addplot[blue] {(ln(x))};  \addplot[red] {x/1.5-0.56}; \end{axis}\end{tikzpicture} \\Rising (concave down)}&
-                          \makecell{\\\begin{tikzpicture}\begin{axis}[xmin=-1.5,  xmax=1.5,   scale=0.2, samples=100] \addplot[blue] {(sin((deg x)))}; \addplot[red] {x}; \end{axis}\end{tikzpicture} \\Rising inflection point}\\
+                      \(\dfrac{dy}{dx}>0\) &
+                      \makecell{\\\begin{tikzpicture}\begin{axis}[axis x line=none, axis y line=none, xmin=-3,  xmax=0.8, scale=0.2, samples=50, unbounded coords=jump] \addplot[blue] {(e^(x)};  \addplot[red] {x/2.5+0.75}; \end{axis}\end{tikzpicture} \\Rising (concave up)}&
+                        \makecell{\\\begin{tikzpicture}\begin{axis}[axis x line=none, axis y line=none, xmin=0.1, xmax=4,   scale=0.2, samples=50, unbounded coords=jump] \addplot[blue] {(ln(x))};  \addplot[red] {x/1.5-0.56}; \end{axis}\end{tikzpicture} \\Rising (concave down)}&
+                          \makecell{\\\begin{tikzpicture}\begin{axis}[axis x line=none, axis y line=none, xmin=-1.5,  xmax=1.5,   scale=0.2, samples=100] \addplot[blue] {(sin((deg x)))}; \addplot[red] {x}; \end{axis}\end{tikzpicture} \\Rising inflection point}\\
                             \hline
                             \(\dfrac{dy}{dx}<0\) &
-                            \makecell{\\\begin{tikzpicture}\begin{axis}[xmin=-.5, xmax=1, ymin=-.5, ymax=.5, scale=0.2, samples=100] \addplot[blue] {(1/(x+1)-1}; \addplot[red] {-x}; \end{axis}\end{tikzpicture} \\Falling (concave up)}&
-                              \makecell{\\\begin{tikzpicture}\begin{axis}[xmin=0,  xmax=1.5, scale=0.2, samples=50, unbounded coords=jump] \addplot[blue] {(2-x*x)^(1/2)};  \addplot[red] {-x+2}; \end{axis}\end{tikzpicture} \\Falling (concave down)}&
-                                \makecell{\\\begin{tikzpicture}\begin{axis}[xmin=1.5,  xmax=4.5,   scale=0.2, samples=100] \addplot[blue] {(sin((deg x)))}; \addplot[red] {-x+3.1415}; \end{axis}\end{tikzpicture} \\Falling inflection point}\\
+                            \makecell{\\\begin{tikzpicture}\begin{axis}[axis x line=none, axis y line=none, xmin=-.5, xmax=1, ymin=-.5, ymax=.5, scale=0.2, samples=100] \addplot[blue] {1/(x+1)-1}; \addplot[red] {-x}; \end{axis}\end{tikzpicture} \\Falling (concave up)}&
+                              \makecell{\\\begin{tikzpicture}\begin{axis}[axis x line=none, axis y line=none, xmin=0,  xmax=1.5, scale=0.2, samples=50, unbounded coords=jump] \addplot[blue] {(2-x*x)^(1/2)};  \addplot[red] {-x+2}; \end{axis}\end{tikzpicture} \\Falling (concave down)}&
+                                \makecell{\\\begin{tikzpicture}\begin{axis}[axis x line=none, axis y line=none, xmin=1.5,  xmax=4.5,   scale=0.2, samples=100] \addplot[blue] {(sin((deg x)))}; \addplot[red] {-x+3.1415}; \end{axis}\end{tikzpicture} \\Falling inflection point}\\
                                   \hline
                                   \(\dfrac{dy}{dx}=0\)&
-                                  \makecell{\\\begin{tikzpicture}\begin{axis}[xmin=-1,  xmax=1,   scale=0.2, samples=50, unbounded coords=jump] \addplot[blue] {(x*x))}; \addplot[red, thick] {0}; \end{axis}\end{tikzpicture} \\Local minimum}&                       \makecell{\\\begin{tikzpicture}\begin{axis}[xmin=-1,  xmax=1,   scale=0.2, samples=50, unbounded coords=jump] \addplot[blue] {(-x*x))}; \addplot[red, very thick] {0}; \end{axis}\end{tikzpicture} \\Local maximum}&
-                                    \makecell{\\\begin{tikzpicture}\begin{axis}[xmin=-1,  xmax=1,   scale=0.2, samples=50, unbounded coords=jump] \addplot[blue] {(x*x*x))}; \addplot[red, thick] {0}; \end{axis}\end{tikzpicture} \(\>\) \begin{tikzpicture}\begin{axis}[xmin=-1,  xmax=1,   scale=0.2, samples=50, unbounded coords=jump] \addplot[blue] {(-x*x*x))}; \addplot[red, thick] {0}; \end{axis}\end{tikzpicture}  \\Stationary inflection point}\\
+                                  \makecell{\\\begin{tikzpicture}\begin{axis}[axis x line=none, axis y line=none, xmin=-1,  xmax=1,   scale=0.2, samples=50, unbounded coords=jump] \addplot[blue] {(x*x)}; \addplot[red, thick] {0}; \end{axis}\end{tikzpicture} \\Local minimum}&                       \makecell{\\\begin{tikzpicture}\begin{axis}[axis x line=none, axis y line=none, xmin=-1,  xmax=1,   scale=0.2, samples=50, unbounded coords=jump] \addplot[blue] {(-x*x)}; \addplot[red, very thick] {0}; \end{axis}\end{tikzpicture} \\Local maximum}&
+                                    \makecell{\\\begin{tikzpicture}\begin{axis}[axis x line=none, axis y line=none, xmin=-1,  xmax=1,   scale=0.2, samples=50, unbounded coords=jump] \addplot[blue] {(x*x*x)}; \addplot[red, thick] {0}; \end{axis}\end{tikzpicture} \(\>\) \begin{tikzpicture}\begin{axis}[axis x line=none, axis y line=none, xmin=-1,  xmax=1,   scale=0.2, samples=50, unbounded coords=jump] \addplot[blue] {(-x*x*x)}; \addplot[red, thick] {0}; \end{axis}\end{tikzpicture}  \\Stationary inflection point}\\
                                       \hline
                     \end{tabularx}
                   \end{table*}
                   \begin{itemize}
                     \item
-                      if \(f^\prime (a) = 0\) and \(f^{\prime\prime}(a) > 0\), then point
-                      \((a, f(a))\) is a local min (curve is concave up)
+                      \(f^\prime (a) = 0, \> f^{\prime\prime}(a) > 0\) \\
+                      \textbf{local min} at \((a, f(a))\) (concave up)
                     \item
-                      if \(f^\prime (a) = 0\) and \(f^{\prime\prime} (a) < 0\), then point
-                      \((a, f(a))\) is local max (curve is concave down)
+                      \(f^\prime (a) = 0, \>  f^{\prime\prime} (a) < 0\) \\
+                      \textbf{local max} at \((a, f(a))\) (concave down)
                     \item
-                      if \(f^{\prime\prime}(a) = 0\), then point \((a, f(a))\) is a point of
-                      inflection
+                      \(f^{\prime\prime}(a) = 0\) \\
+                      \textbf{point of inflection} at \((a, f(a))\)
                     \item
-                      if also \(f^\prime(a)=0\), then it is a stationary point of inflection
+                      \(f^{\prime\prime}(a) = 0, \> f^\prime(a)=0\) \\
+                      stationary point of inflection at \((a, f(a)\)
                   \end{itemize}
 
                   \subsection*{Implicit Differentiation}
 
                   \[{\frac{dp}{dx}} = {\frac{dq}{dx}} \quad \text{and} \quad {\frac{dp}{dy}} = {\frac{dq}{dy}}\]
 
-                  \noindent \colorbox{cas}{\textbf{On CAS:}}\\
-                  Action \(\rightarrow\) Calculation \(\rightarrow\) \texttt{impDiff(y\^{}2+ax=5,\ x,\ y)}\\
-                  Returns \(y^\prime= \dots\).
-
-                  \subsection*{Integration}
-
-                  \[\int f(x) \cdot dx = F(x) + c \quad \text{where } F^\prime(x) = f(x)\]
-
-                  \subsection*{Integral laws}
-
-                  \renewcommand{\arraystretch}{1.4}
-                  \begin{tabularx}{\columnwidth}{rX}
-                    \hline
-                    \(f(x)\) & \(\int f(x) \cdot dx\) \\
-                    \hline
-                    \(k\) (constant) & \(kx + c\)\\
-                    \(x^n\) & \(\dfrac{1}{n+1} x^{n+1}\) \\
-                    \(a x^{-n}\) &\(a \cdot \log_e |x| + c\)\\
-                    \(\dfrac{1}{ax+b}\) &\(\dfrac{1}{a} \log_e (ax+b) + c\)\\
-                    \((ax+b)^n\) & \(\dfrac{1}{a(n+1)}(ax+b)^{n-1} + c\>|\>n\ne 1\)\\
-                    \((ax+b)^{-1}\) & \(\dfrac{1}{a}\log_e |ax+b|+c\)\\
-                    \(e^{kx}\) & \(\dfrac{1}{k} e^{kx} + c\)\\
-                    \(e^k\) & \(e^kx + c\)\\
-                    \(\sin kx\) & \(\dfrac{-1}{k} \cos (kx) + c\)\\
-                    \(\cos kx\) & \(\dfrac{1}{k} \sin (kx) + c\)\\
-                    \(\sec^2 kx\) & \(\dfrac{1}{k} \tan(kx) + c\)\\
-                    \(\dfrac{1}{\sqrt{a^2-x^2}}\) & \(\sin^{-1} \dfrac{x}{a} + c \>\vert\> a>0\)\\
-                    \(\dfrac{-1}{\sqrt{a^2-x^2}}\) & \(\cos^{-1} \dfrac{x}{a} + c \>\vert\> a>0\)\\
-                    \(\frac{a}{a^2-x^2}\) & \(\tan^{-1} \frac{x}{a} + c\)\\
-                    \(\frac{f^\prime (x)}{f(x)}\) & \(\log_e f(x) + c\)\\
-                    \(\int f(u) \cdot \frac{du}{dx} \cdot dx\) & \(\int f(u) \cdot du\) (substitution)\\
-                    \(f(x) \cdot g(x)\) & \(\int [f^\prime(x) \cdot g(x)] dx + \int [g^\prime(x) f(x)] dx\)\\
-                    \hline
-                  \end{tabularx}
-
-                  Note \(\sin^{-1} {x \over a} + \cos^{-1} {x \over a}\) is constant \(\forall x \in (-a, a)\)
-
-                  \subsection*{Definite integrals}
-
-                  \[\int_a^b f(x) \cdot dx = [F(x)]_a^b=F(b)-F(a)\]
+                  \begin{cas}
+                    Action \(\rightarrow\) Calculation \\
+                      \-\hspace{1em}\texttt{impDiff(y\^{}2+ax=5,\ x,\ y)}
+                  \end{cas}
 
-                  \begin{itemize}
+                  \subsection*{Function of the dependent
+                  variable}
 
-                    \item
-                      Signed area enclosed by\\
-                      \(\> y=f(x), \quad y=0, \quad x=a, \quad x=b\).
-                    \item
-                      \emph{Integrand} is \(f\).
-                  \end{itemize}
+                  If \({\frac{dy}{dx}}=g(y)\), then
+                  \(\frac{dx}{dy} = 1 \div \frac{dy}{dx} = \frac{1}{g(y)}\). Integrate both sides to solve equation. Only add \(c\) on one side. Express
+                  \(e^c\) as \(A\).
 
-                  \subsubsection*{Properties}
+                  \subsection*{Reciprocal derivatives}
 
-                  \[\int^b_a f(x) \> dx = \int^c_a f(x) \> dx + \int^b_c f(x) \> dx\]
+                  \[\frac{1}{\frac{dy}{dx}} = \frac{dx}{dy}\]
+
+                  \subsection*{Differentiating \(x=f(y)\)}
+                  Find \(\dfrac{dx}{dy}\), then \(\dfrac{dy}{dx} = \dfrac{1}{\left(\dfrac{dx}{dy}\right)}\)
 
-                  \[\int^a_a f(x) \> dx = 0\]
+                  \subsection*{Parametric equations}
 
-                  \[\int^b_a k \cdot f(x) \> dx = k \int^b_a f(x) \> dx\]
 
-                  \[\int^b_a f(x) \pm g(x) \> dx = \int^b_a f(x) \> dx \pm \int^b_a g(x) \> dx\]
+                  \begin{align*}
+                    \dfrac{dy}{dt} &= \dfrac{dy}{dx} \cdot \dfrac{dx}{dt} \\
+                    \therefore \dfrac{dy}{dx} &= \dfrac{\left(\dfrac{dy}{dt}\right)}{\left(\dfrac{dx}{dt}\right)} \text{ provided } \dfrac{dx}{dt} \ne 0 \\
+                    \dfrac{d^2y}{dx^2} &= \dfrac{\left(\dfrac{dy^\prime}{dt}\right)}{\left(\dfrac{dx}{dt}\right)} \text{ where } y^\prime = \dfrac{dy}{dx}
+                  \end{align*}
 
-                  \[\int^b_a f(x) \> dx = - \int^a_b f(x) \> dx\]
+                \subsection*{Integration}
+
+                \[\int f(x) \cdot dx = F(x) + c \quad \text{where } F^\prime(x) = f(x)\]
+
+                  \subsubsection*{Properties}
+
+                  \begin{align*}
+                    \int^b_a f(x) \> dx &= \int^c_a f(x) \> dx + \int^b_c f(x) \> dx \\
+                    \int^a_a f(x) \> dx &= 0 \\
+                    \int^b_a k \cdot f(x) \> dx &= k \int^b_a f(x) \> dx \\
+                    \int^b_a f(x) \pm g(x) \> dx &= \int^b_a f(x) \> dx \pm \int^b_a g(x) \> dx \\
+                    \int^b_a f(x) \> dx &= - \int^a_b f(x) \> dx \\
+                  \end{align*}
 
                   \subsection*{Integration by substitution}
 
                   \[\int f(u) {\frac{du}{dx}} \cdot dx = \int f(u) \cdot du\]
 
-                  \noindent Note \(f(u)\) must be 1:1 \(\implies\) one \(x\) for each \(y\)
+                  \begin{warning}
+                    \(\boldsymbol{f(u)}\) must be 1:1 \(\boldsymbol{\implies}\) one \(\boldsymbol{x}\) for each \(\boldsymbol{y}\)
+                  \end{warning}
                   \begin{align*}\text{e.g. for } y&=\int(2x+1)\sqrt{x+4} \cdot dx\\
                     \text{let } u&=x+4\\
                     \implies& {\frac{du}{dx}} = 1\\
                       \(\sin 2x = 2 \sin x \cos x\)
                   \end{itemize}
 
+                  \subsection*{Separation of variables}
+
+                  If \({\frac{dy}{dx}}=f(x)g(y)\), then:
+
+                  \[\int f(x) \> dx = \int \frac{1}{g(y)} \> dy\]
+
                   \subsection*{Partial fractions}
 
-                  \colorbox{cas}{On CAS:}\\
-                  \indent Action \(\rightarrow\) Transformation \(\rightarrow\)
-                  \texttt{expand/combine}\\
-                  \indent Interactive \(\rightarrow\) Transformation \(\rightarrow\)
-                  Expand \(\rightarrow\) Partial
+                  To factorise \(f(x) = \frac{\delta}{\alpha \cdot \beta}\):
+                  \begin{align*}
+                    \dfrac{\delta}{\alpha \cdot \beta \cdot \gamma} &= \dfrac{A}{\alpha} + \dfrac{B}{\beta} + \dfrac{C}{\gamma} \tag{1} \\
+                    \text{Multiply by } & (\alpha \cdot \beta \cdot \gamma) \text{:} \\
+                    \delta &= \beta\gamma A + \alpha\gamma B +\alpha\beta C \tag{2} \\
+                    \text{Substitute } x &= \{\alpha, \beta, \gamma\} \text{ into (2) to find denominators}
+                  \end{align*}
 
-                  \subsection*{Graphing integrals on CAS}
+                  \subsubsection*{Repeated linear factors}
 
-                  \colorbox{cas}{In main:} Interactive \(\rightarrow\) Calculation \(\rightarrow\)
-                  \(\int\) (\(\rightarrow\) Definite)\\
-                  Restrictions: \texttt{Define\ f(x)=..} then \texttt{f(x)\textbar{}x\textgreater{}..}
+                  \[ \dfrac{p(x)}{(x-a)^n} = \dfrac{A_1}{(x-a)} + \dfrac{A_2}{(x-a)^2} + \dots + \dfrac{A_n}{(x-a)^n} \]
 
-                  \subsection*{Applications of antidifferentiation}
+                  \subsubsection*{Irreducible quadratic factors}
 
-                  \begin{itemize}
+                  \[ \text{e.g. } \dfrac{3x-4}{(2x-3)(x^2+5)} = \dfrac{A}{2x-3} + \dfrac{Bx+C}{x^2+5} \]
 
-                    \item
-                      \(x\)-intercepts of \(y=f(x)\) identify \(x\)-coordinates of
-                      stationary points on \(y=F(x)\)
-                    \item
-                      nature of stationary points is determined by sign of \(y=f(x)\) on
-                      either side of its \(x\)-intercepts
-                    \item
-                      if \(f(x)\) is a polynomial of degree \(n\), then \(F(x)\) has degree
-                      \(n+1\)
-                  \end{itemize}
+                  \begin{cas}
+                    Action \(\rightarrow\) Transformation:\\
+                    \-\hspace{1em} \texttt{expand(..., x)}
 
-                  To find stationary points of a function, substitute \(x\) value of given
-                  point into derivative. Solve for \({\frac{dy}{dx}}=0\). Integrate to find
-                  original function.
+                    To reverse, use \texttt{combine(...)}
+                  \end{cas}
+
+                  \subsection*{Integrating \(\boldsymbol{\dfrac{dy}{dx} = g(y)}\)}
+
+                  \[ \text{if } \dfrac{dy}{dx} = g(y), \text{ then } x = \int{\dfrac{1}{g(y)}} \> dy \]
+
+                  \subsection*{Graphing integrals on CAS}
+
+                  \begin{cas}
+                    \textbf{In main:} Interactive \(\rightarrow\) Calculation \(\rightarrow\) \(\int\)\\
+                    For restrictions, \texttt{Define\ f(x)=...} then \texttt{f(x)\textbar{}x\textgreater{}...}
+                  \end{cas}
 
                   \subsection*{Solids of revolution}
 
                   Approximate as sum of infinitesimally-thick cylinders
 
-                  \subsubsection*{Rotation about \(x\)-axis}
+                  \subsubsection*{Rotation about \(\boldsymbol{x}\)-axis}
 
-                  \begin{align*}
-                    V &= \int^{x=b}_{x-a} \pi y^2 \> dx \\
-                    &= \pi \int^b_a (f(x))^2 \> dx
-                  \end{align*}
+                  \[ V = \pi\int^{x=b}_{x=a} f(x)^2 \> dx \]
 
-                  \subsubsection*{Rotation about \(y\)-axis}
+                  \subsubsection*{Rotation about \(\boldsymbol{y}\)-axis}
 
                   \begin{align*}
-                    V &= \int^{y=b}_{y=a} \pi x^2 \> dy \\
-                    &= \pi \int^b_a (f(y))^2 \> dy
+                    V &= \pi \int^{y=b}_{y=a} x^2 \> dy \\
+                    &= \pi \int^{y=b}_{y=a} (f(y))^2 \> dy
                   \end{align*}
 
-                  \subsubsection*{Regions not bound by \(y=0\)}
+                  \subsubsection*{Regions not bound by \(\boldsymbol{y=0}\)}
 
                   \[V = \pi \int^b_a f(x)^2 - g(x)^2 \> dx\]
                   \hfill where \(f(x) > g(x)\)
 
                   \subsection*{Length of a curve}
 
-                  \[L = \int^b_a \sqrt{1 + ({\frac{dy}{dx}})^2} \> dx \quad \text{(Cartesian)}\]
+                  For length of \(f(x)\) from \(x=a \rightarrow x=b\):
+                  \begin{align*}
+                    &\text{Cartesian} \> & L &= \int^b_a \sqrt{1 + \left(\dfrac{dy}{dx}\right)^2} \> dx \\
+                    &\text{Parametric} \> & L & = \int^b_a \sqrt{\left(\dfrac{dx}{dt}\right)^2 + \left(\dfrac{dy}{dt}\right)^2} \> dt
+                  \end{align*}
+
+                  \begin{cas}
+                    \begin{enumerate}[label=\alph*), leftmargin=5mm]
+                      \item Evaluate formula
+                      \item Interactive \(\rightarrow\) Calculation \(\rightarrow\) Line \(\rightarrow\) \texttt{arcLen}
+                    \end{enumerate}
+                  \end{cas}
+
+                  \subsection*{Applications of antidifferentiation}
 
-                  \[L = \int^b_a \sqrt{{\frac{dx}{dt}} + ({\frac{dy}{dt}})^2} \> dt \quad \text{(parametric)}\]
+                  \begin{itemize}
+
+                    \item
+                      \(x\)-intercepts of \(y=f(x)\) identify \(x\)-coordinates of
+                      stationary points on \(y=F(x)\)
+                    \item
+                      nature of stationary points is determined by sign of \(y=f(x)\) on
+                      either side of its \(x\)-intercepts
+                    \item
+                      if \(f(x)\) is a polynomial of degree \(n\), then \(F(x)\) has degree
+                      \(n+1\)
+                  \end{itemize}
 
-                  \noindent \colorbox{cas}{On CAS:}\\
-                  \indent Evaluate formula,\\
-                  \indent or Interactive \(\rightarrow\) Calculation
-                  \(\rightarrow\) Line \(\rightarrow\) \texttt{arcLen}
+                  To find stationary points of a function, substitute \(x\) value of given
+                  point into derivative. Solve for \({\frac{dy}{dx}}=0\). Integrate to find
+                  original function.
 
                   \subsection*{Rates}
 
                   \subsubsection*{Gradient at a point on parametric curve}
 
-                  \[{\frac{dy}{dx}} = {{\frac{dy}{dt}} \div {\frac{dx}{dt}}} \> \vert \> {\frac{dx}{dt}} \ne 0\]
+                  \[{\frac{dy}{dx}} = {{\frac{dy}{dt}} \div {\frac{dx}{dt}}} \> \vert \> {\frac{dx}{dt}} \ne 0 \text{ (chain rule)}\]
 
                   \[\frac{d^2}{dx^2} = \frac{d(y^\prime)}{dx} = {\frac{dy^\prime}{dt} \div {\frac{dx}{dt}}} \> \vert \> y^\prime = {\frac{dy}{dx}}\]
 
 
                   \[f(x) = \frac{P(x)}{Q(x)} \quad \text{where } P, Q \text{ are polynomial functions}\]
 
-                  \subsubsection*{Addition of ordinates}
-
-                  \begin{itemize}
-
-                    \item
-                      when two graphs have the same ordinate, \(y\)-coordinate is double the
-                      ordinate
-                    \item
-                      when two graphs have opposite ordinates, \(y\)-coordinate is 0 i.e.
-                      (\(x\)-intercept)
-                    \item
-                      when one of the ordinates is 0, the resulting ordinate is equal to the
-                      other ordinate
-                  \end{itemize}
-
                   \subsection*{Fundamental theorem of calculus}
 
                   If \(f\) is continuous on \([a, b]\), then
                   \textbf{Degree} - highest power of highest derivative\\
                   e.g. \({\left(\dfrac{dy^2}{d^2} x\right)}^3\) \qquad order 2, degree 3
 
-                  \subsubsection*{Verifying solutions}
+                  \begin{warning}
+                    To verify solutions, find \(\frac{dy}{dx}\) from \(y\) and substitute into original
+                  \end{warning}
 
-                  Start with \(y=\dots\), and differentiate. Substitute into original
-                  equation.
 
-                  \subsubsection*{Function of the dependent
-                  variable}
 
-                  If \({\frac{dy}{dx}}=g(y)\), then
-                  \(\frac{dx}{dy} = 1 \div \frac{dy}{dx} = \frac{1}{g(y)}\). Integrate both sides to solve equation. Only add \(c\) on one side. Express
-                  \(e^c\) as \(A\).
+                  \subsubsection*{Mixing problems}
 
+                  \[\left(\frac{dm}{dt}\right)_\Sigma = \left(\frac{dm}{dt}\right)_{\text{in}} - \left(\frac{dm}{dt}_{\text{out}}\right)\]
 
+                  \subsection*{Euler's method}
 
-                  \subsubsection*{Mixing problems}
+                  \[\dfrac{f(x+h) - f(x)}{h} \approx f^\prime (x) \quad \text{for small } h\]
 
-                  \[\left(\frac{dm}{dt}\right)_\Sigma = \left(\frac{dm}{dt}\right)_{\text{in}} - \left(\frac{dm}{dt}_{\text{out}}\right)\]
+                  \[\implies f(x+h) \approx f(x) + hf^\prime(x)\]
 
-                  \subsubsection*{Separation of variables}
+                  \begin{theorembox}{}
+                    If \(\dfrac{dy}{dx} = g(x)\) with \(x_0 = a\) and \(y_0 = b\), then:
+                    \begin{align*}
+                      x_{n+1} &= x_n + h \\
+                      y_{n+1} &= y_n + hg(x_n)
+                    \end{align*}
+                  \end{theorembox}
 
-                  If \({\frac{dy}{dx}}=f(x)g(y)\), then:
 
-                  \[\int f(x) \> dx = \int \frac{1}{g(y)} \> dy\]
 
-                  \subsubsection*{Euler's method for solving DEs}
+                  \include{calculus-rules}
 
-                  \[\frac{f(x+h) - f(x)}{h} \approx f^\prime (x) \quad \text{for small } h\]
+    \section{Kinematics \& Mechanics}
 
-                  \[\implies f(x+h) \approx f(x) + hf^\prime(x)\]
+      \subsection*{Constant acceleration}
+
+      \begin{itemize}
+        \item \textbf{Position} - relative to origin
+        \item \textbf{Displacement} - relative to starting point
+      \end{itemize}
+
+      \subsubsection*{Velocity-time graphs}
+
+      \begin{description}[nosep, labelindent=0.5cm, leftmargin=0.5\columnwidth]
+        \item[Displacement:] \textit{signed} area
+        \item[Distance travelled:] \textit{total} area
+      \end{description}
+
+      \[ \text{acceleration} = \frac{d^2x}{dt^2} = \frac{dv}{dt} = v\frac{dv}{dx} = \frac{d}{dx}\left(\frac{1}{2}v^2\right) \]
+
+        \begin{center}
+          \renewcommand{\arraystretch}{1}
+          \begin{tabular}{ l r }
+            \hline & no \\ \hline
+            \(v=u+at\) & \(x\) \\
+            \(v^2 = u^2+2as\) & \(t\) \\
+            \(s = \frac{1}{2} (v+u)t\) & \(a\) \\
+            \(s = ut + \frac{1}{2} at^2\) & \(v\) \\
+            \(s = vt- \frac{1}{2} at^2\) & \(u\) \\ \hline
+          \end{tabular}
+        \end{center}
+
+        \[ v_{\text{avg}} = \frac{\Delta\text{position}}{\Delta t} \]
+        \begin{align*}
+          \text{speed} &= |{\text{velocity}}| \\
+          &= \sqrt{v_x^2 + v_y^2 + v_z^2}
+        \end{align*}
+
+        \noindent \textbf{Distance travelled between \(t=a \rightarrow t=b\):}
+        \begin{align*}
+          &= \int^{b}_{a}{\sqrt{\left(\frac{dx}{dt}\right)^2 + \left(\frac{dy}{dt}\right)^2}} \> dt \tag{2D} \\
+          &= \int^{t=b}_{t=a}{\dfrac{dx}{dt}} \> dt \tag{linear}
+        \end{align*}
+
+        \noindent \textbf{Shortest distance between \(\boldsymbol{r}(t_0)\) and \(\boldsymbol{r}(t_1)\):}
+        \[ = |\boldsymbol{r}(t_1) - \boldsymbol{r}(t_2)| \]
+
+      \subsection*{Vector functions}
+
+        \[ \boldsymbol{r}(t) = x \boldsymbol{i} + y \boldsymbol{j} + z \boldsymbol{k} \]
+
+        \begin{itemize}
+          \item If \(\boldsymbol{r}(t) \equiv\) position with time, then the graph of endpoints of \(\boldsymbol{r}(t) \equiv\) Cartesian path
+          \item Domain of \(\boldsymbol{r}(t)\) is the range of \(x(t)\)
+          \item Range of \(\boldsymbol{r}(t)\) is the range of \(y(t)\)
+        \end{itemize}
+
+      \subsection*{Vector calculus}
+
+      \subsubsection*{Derivative}
+
+        Let \(\boldsymbol{r}(t)=x(t)\boldsymbol{i} + y(t)\boldsymbol(j)\). If both \(x(t)\) and \(y(t)\) are differentiable, then:
+        \[ \boldsymbol{r}(t)=x(t)\boldsymbol{i}+y(t)\boldsymbol{j} \]
 
-                \end{multicols}
-              \end{document}
+      \subfile{dynamics}
+      \subfile{statistics}
+  \end{multicols}
+\end{document}