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[spec] start antidifferentiation revision
author
Andrew Lorimer
<andrew@lorimer.id.au>
Thu, 4 Apr 2019 01:31:57 +0000
(12:31 +1100)
committer
Andrew Lorimer
<andrew@lorimer.id.au>
Thu, 4 Apr 2019 01:31:57 +0000
(12:31 +1100)
spec/calculus.md
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diff --git
a/spec/calculus.md
b/spec/calculus.md
index c2390847c889916098938a0431b7fd82a7e53440..167a7e78c2e649b962f41940d9d4494fdd46467a 100644
(file)
--- a/
spec/calculus.md
+++ b/
spec/calculus.md
@@
-207,13
+207,23
@@
Order of polynomial $n$th derivative decrements each time the derivative is take
![](graphics/second-derivatives.png)
![](graphics/second-derivatives.png)
+## Implicit Differentiation
+
+On CAS: Action $\rightarrow$ Calculation $\rightarrow$ `impDiff(y^2+ax=5, x, y)`. Returns $y^\prime= \dots$.
+
+Used for differentiating circles etc.
+
+If $p$ and $q$ are expressions in $x$ and $y$ such that $p=q$, for all $x$ nd $y$, then:
+
+$${dp \over dx} = {dq \over dx} \quad \text{and} \quad {dp \over dy} = {dq \over dy}$$
+
## Antidifferentiation
$$y={x^{n+1} \over n+1} + c$$
## Integration
## Antidifferentiation
$$y={x^{n+1} \over n+1} + c$$
## Integration
-$$\int f(x) dx = F(x) + c$$
+$$\int f(x) dx = F(x) + c
\quad \text{where } F^\prime(x) = f(x)
$$
- area enclosed by curves
- $+c$ should be shown on each step without $\int$
- area enclosed by curves
- $+c$ should be shown on each step without $\int$
@@
-240,6
+250,10
@@
$\int k f(x) dx = k \int f(x) dx$
| ${1 \over {ax+b}}$ | ${1 \over a} \log_e (ax+b) + c$ |
| $(ax+b)^n$ | ${1 \over {a(n+1)}}(ax+b)^{n-1} + c$ |
| ${1 \over {ax+b}}$ | ${1 \over a} \log_e (ax+b) + c$ |
| $(ax+b)^n$ | ${1 \over {a(n+1)}}(ax+b)^{n-1} + c$ |
+### Definite integrals
+
+$$\int_a^b f(x) \cdot dx = [F(x)]_a^b=F(b)-F(a)_{}$$
+
## Applications of antidifferentiation
- $x$-intercepts of $y=f(x)$ identify $x$-coordinates of stationary points on $y=F(x)$
## Applications of antidifferentiation
- $x$-intercepts of $y=f(x)$ identify $x$-coordinates of stationary points on $y=F(x)$
@@
-269,16
+283,3
@@
$$f(x) = {P(x) \over Q(x)} \quad \text{where } P, Q \text{ are polynomial functi
- when two graphs have the same ordinate, $y$-coordinate is double the ordinate
- when two graphs have opposite ordinates, $y$-coordinate is 0 i.e. ($x$-intercept)
- when one of the ordinates is 0, the resulting ordinate is equal to the other ordinate
- when two graphs have the same ordinate, $y$-coordinate is double the ordinate
- when two graphs have opposite ordinates, $y$-coordinate is 0 i.e. ($x$-intercept)
- when one of the ordinates is 0, the resulting ordinate is equal to the other ordinate
-
-
-## Implicit Differentiation
-
-On CAS: Action $\rightarrow$ Calculation $\rightarrow$ `impDiff(y^2+ax=5, x, y)`. Returns $y^\prime= \dots$.
-
-Used for differentiating circles etc.
-
-If $p$ and $q$ are expressions in $x$ and $y$ such that $p=q$, for all $x$ nd $y$, then:
-
-$${dp \over dx} = {dq \over dx} \quad \text{and} \quad {dp \over dy} = {dq \over dy}$$
-
-