From 7d4849ee6239a431d14e0b2e800e13b365c1d58a Mon Sep 17 00:00:00 2001 From: Andrew Lorimer Date: Tue, 5 Feb 2019 12:42:16 +1100 Subject: [PATCH] molar volume --- chem/gas.md | 17 ++++++++++++----- 1 file changed, 12 insertions(+), 5 deletions(-) diff --git a/chem/gas.md b/chem/gas.md index 1848d38..3020896 100644 --- a/chem/gas.md +++ b/chem/gas.md @@ -8,10 +8,11 @@ $${P_1 V_1 \over T_1} = {P_2 V_2 \over T_2}$$ $$PV=nRT$$ -where $R =$ universal gas constant $= 8.31 \text{J} \text{K}^{-1} \text{mol}^{-1}$ -$P$ is measured in kPa -$V$ is measured in L -$T$ is measured in K +where +$R =$ universal gas constant $= 8.31 \text{ J K}^{-1} \text{mol}^{-1}$ +$P$ is measured in kPa +$V$ is measured in L +$T$ is measured in K $n$ is no of mol of gas @@ -22,7 +23,7 @@ $n$ is no of mol of gas > Equal volumes of all gases measured at the same temperature and pressure contain the same number of gas particles -$\therefore$ 1 mole of any gas at SLC occupies 24.8L - **molar gas voluem** +$\therefore$ 1 mole of any gas at SLC occupies 24.8L - **molar gas volume** $$n={V \over V_M}$$ @@ -31,3 +32,9 @@ $V$ = actual volume (in litres) $V_m$ = molar volume of gas $$\therefore n_{SLC} = {V \over 24.8}$$ + +## Molar volume + +Volume of a mole of a gas - depends on pressure & temperature +Molar gas volume = $V_M = 24.8 \text{ L mol}^{-1}$ at SLC +Use $n = {V \over V_m}$ like $n={m \over M}$ \ No newline at end of file -- 2.43.2