compat / obstack.con commit trace2: report peak memory usage of the process (26c6f25)
   1/* obstack.c - subroutines used implicitly by object stack macros
   2   Copyright (C) 1988, 1989, 1990, 1991, 1992, 1993, 1994, 1996, 1997, 1998,
   3   1999, 2000, 2001, 2002, 2003, 2004, 2005 Free Software Foundation, Inc.
   4   This file is part of the GNU C Library.
   5
   6   The GNU C Library is free software; you can redistribute it and/or
   7   modify it under the terms of the GNU Lesser General Public
   8   License as published by the Free Software Foundation; either
   9   version 2.1 of the License, or (at your option) any later version.
  10
  11   The GNU C Library is distributed in the hope that it will be useful,
  12   but WITHOUT ANY WARRANTY; without even the implied warranty of
  13   MERCHANTABILITY or FITNESS FOR A PARTICULAR PURPOSE.  See the GNU
  14   Lesser General Public License for more details.
  15
  16   You should have received a copy of the GNU Lesser General Public
  17   License along with the GNU C Library; if not, see
  18   <http://www.gnu.org/licenses/>.  */
  19
  20#include "git-compat-util.h"
  21#include <gettext.h>
  22#include "obstack.h"
  23
  24/* NOTE BEFORE MODIFYING THIS FILE: This version number must be
  25   incremented whenever callers compiled using an old obstack.h can no
  26   longer properly call the functions in this obstack.c.  */
  27#define OBSTACK_INTERFACE_VERSION 1
  28
  29/* Comment out all this code if we are using the GNU C Library, and are not
  30   actually compiling the library itself, and the installed library
  31   supports the same library interface we do.  This code is part of the GNU
  32   C Library, but also included in many other GNU distributions.  Compiling
  33   and linking in this code is a waste when using the GNU C library
  34   (especially if it is a shared library).  Rather than having every GNU
  35   program understand `configure --with-gnu-libc' and omit the object
  36   files, it is simpler to just do this in the source for each such file.  */
  37
  38#include <stdio.h>              /* Random thing to get __GNU_LIBRARY__.  */
  39#if !defined _LIBC && defined __GNU_LIBRARY__ && __GNU_LIBRARY__ > 1
  40# include <gnu-versions.h>
  41# if _GNU_OBSTACK_INTERFACE_VERSION == OBSTACK_INTERFACE_VERSION
  42#  define ELIDE_CODE
  43# endif
  44#endif
  45
  46#include <stddef.h>
  47
  48#ifndef ELIDE_CODE
  49
  50
  51# if HAVE_INTTYPES_H
  52#  include <inttypes.h>
  53# endif
  54# if HAVE_STDINT_H || defined _LIBC
  55#  include <stdint.h>
  56# endif
  57
  58/* Determine default alignment.  */
  59union fooround
  60{
  61  uintmax_t i;
  62  long double d;
  63  void *p;
  64};
  65struct fooalign
  66{
  67  char c;
  68  union fooround u;
  69};
  70/* If malloc were really smart, it would round addresses to DEFAULT_ALIGNMENT.
  71   But in fact it might be less smart and round addresses to as much as
  72   DEFAULT_ROUNDING.  So we prepare for it to do that.  */
  73enum
  74  {
  75    DEFAULT_ALIGNMENT = offsetof (struct fooalign, u),
  76    DEFAULT_ROUNDING = sizeof (union fooround)
  77  };
  78
  79/* When we copy a long block of data, this is the unit to do it with.
  80   On some machines, copying successive ints does not work;
  81   in such a case, redefine COPYING_UNIT to `long' (if that works)
  82   or `char' as a last resort.  */
  83# ifndef COPYING_UNIT
  84#  define COPYING_UNIT int
  85# endif
  86
  87
  88/* The functions allocating more room by calling `obstack_chunk_alloc'
  89   jump to the handler pointed to by `obstack_alloc_failed_handler'.
  90   This can be set to a user defined function which should either
  91   abort gracefully or use longjump - but shouldn't return.  This
  92   variable by default points to the internal function
  93   `print_and_abort'.  */
  94static void print_and_abort (void);
  95void (*obstack_alloc_failed_handler) (void) = print_and_abort;
  96
  97# ifdef _LIBC
  98#  if SHLIB_COMPAT (libc, GLIBC_2_0, GLIBC_2_3_4)
  99/* A looong time ago (before 1994, anyway; we're not sure) this global variable
 100   was used by non-GNU-C macros to avoid multiple evaluation.  The GNU C
 101   library still exports it because somebody might use it.  */
 102struct obstack *_obstack_compat;
 103compat_symbol (libc, _obstack_compat, _obstack, GLIBC_2_0);
 104#  endif
 105# endif
 106
 107/* Define a macro that either calls functions with the traditional malloc/free
 108   calling interface, or calls functions with the mmalloc/mfree interface
 109   (that adds an extra first argument), based on the state of use_extra_arg.
 110   For free, do not use ?:, since some compilers, like the MIPS compilers,
 111   do not allow (expr) ? void : void.  */
 112
 113# define CALL_CHUNKFUN(h, size) \
 114  (((h) -> use_extra_arg) \
 115   ? (*(h)->chunkfun.extra) ((h)->extra_arg, (size)) \
 116   : (*(h)->chunkfun.plain) ((size)))
 117
 118# define CALL_FREEFUN(h, old_chunk) \
 119  do { \
 120    if ((h) -> use_extra_arg) \
 121      (*(h)->freefun.extra) ((h)->extra_arg, (old_chunk)); \
 122    else \
 123      (*(h)->freefun.plain) ((old_chunk)); \
 124  } while (0)
 125
 126\f
 127/* Initialize an obstack H for use.  Specify chunk size SIZE (0 means default).
 128   Objects start on multiples of ALIGNMENT (0 means use default).
 129   CHUNKFUN is the function to use to allocate chunks,
 130   and FREEFUN the function to free them.
 131
 132   Return nonzero if successful, calls obstack_alloc_failed_handler if
 133   allocation fails.  */
 134
 135int
 136_obstack_begin (struct obstack *h,
 137                int size, int alignment,
 138                void *(*chunkfun) (long),
 139                void (*freefun) (void *))
 140{
 141  register struct _obstack_chunk *chunk; /* points to new chunk */
 142
 143  if (alignment == 0)
 144    alignment = DEFAULT_ALIGNMENT;
 145  if (size == 0)
 146    /* Default size is what GNU malloc can fit in a 4096-byte block.  */
 147    {
 148      /* 12 is sizeof (mhead) and 4 is EXTRA from GNU malloc.
 149         Use the values for range checking, because if range checking is off,
 150         the extra bytes won't be missed terribly, but if range checking is on
 151         and we used a larger request, a whole extra 4096 bytes would be
 152         allocated.
 153
 154         These number are irrelevant to the new GNU malloc.  I suspect it is
 155         less sensitive to the size of the request.  */
 156      int extra = ((((12 + DEFAULT_ROUNDING - 1) & ~(DEFAULT_ROUNDING - 1))
 157                    + 4 + DEFAULT_ROUNDING - 1)
 158                   & ~(DEFAULT_ROUNDING - 1));
 159      size = 4096 - extra;
 160    }
 161
 162  h->chunkfun.plain = chunkfun;
 163  h->freefun.plain = freefun;
 164  h->chunk_size = size;
 165  h->alignment_mask = alignment - 1;
 166  h->use_extra_arg = 0;
 167
 168  chunk = h->chunk = CALL_CHUNKFUN (h, h -> chunk_size);
 169  if (!chunk)
 170    (*obstack_alloc_failed_handler) ();
 171  h->next_free = h->object_base = __PTR_ALIGN ((char *) chunk, chunk->contents,
 172                                               alignment - 1);
 173  h->chunk_limit = chunk->limit
 174    = (char *) chunk + h->chunk_size;
 175  chunk->prev = NULL;
 176  /* The initial chunk now contains no empty object.  */
 177  h->maybe_empty_object = 0;
 178  h->alloc_failed = 0;
 179  return 1;
 180}
 181
 182int
 183_obstack_begin_1 (struct obstack *h, int size, int alignment,
 184                  void *(*chunkfun) (void *, long),
 185                  void (*freefun) (void *, void *),
 186                  void *arg)
 187{
 188  register struct _obstack_chunk *chunk; /* points to new chunk */
 189
 190  if (alignment == 0)
 191    alignment = DEFAULT_ALIGNMENT;
 192  if (size == 0)
 193    /* Default size is what GNU malloc can fit in a 4096-byte block.  */
 194    {
 195      /* 12 is sizeof (mhead) and 4 is EXTRA from GNU malloc.
 196         Use the values for range checking, because if range checking is off,
 197         the extra bytes won't be missed terribly, but if range checking is on
 198         and we used a larger request, a whole extra 4096 bytes would be
 199         allocated.
 200
 201         These number are irrelevant to the new GNU malloc.  I suspect it is
 202         less sensitive to the size of the request.  */
 203      int extra = ((((12 + DEFAULT_ROUNDING - 1) & ~(DEFAULT_ROUNDING - 1))
 204                    + 4 + DEFAULT_ROUNDING - 1)
 205                   & ~(DEFAULT_ROUNDING - 1));
 206      size = 4096 - extra;
 207    }
 208
 209  h->chunkfun.extra = (struct _obstack_chunk * (*)(void *,long)) chunkfun;
 210  h->freefun.extra = (void (*) (void *, struct _obstack_chunk *)) freefun;
 211
 212  h->chunk_size = size;
 213  h->alignment_mask = alignment - 1;
 214  h->extra_arg = arg;
 215  h->use_extra_arg = 1;
 216
 217  chunk = h->chunk = CALL_CHUNKFUN (h, h -> chunk_size);
 218  if (!chunk)
 219    (*obstack_alloc_failed_handler) ();
 220  h->next_free = h->object_base = __PTR_ALIGN ((char *) chunk, chunk->contents,
 221                                               alignment - 1);
 222  h->chunk_limit = chunk->limit
 223    = (char *) chunk + h->chunk_size;
 224  chunk->prev = NULL;
 225  /* The initial chunk now contains no empty object.  */
 226  h->maybe_empty_object = 0;
 227  h->alloc_failed = 0;
 228  return 1;
 229}
 230
 231/* Allocate a new current chunk for the obstack *H
 232   on the assumption that LENGTH bytes need to be added
 233   to the current object, or a new object of length LENGTH allocated.
 234   Copies any partial object from the end of the old chunk
 235   to the beginning of the new one.  */
 236
 237void
 238_obstack_newchunk (struct obstack *h, int length)
 239{
 240  register struct _obstack_chunk *old_chunk = h->chunk;
 241  register struct _obstack_chunk *new_chunk;
 242  register long new_size;
 243  register long obj_size = h->next_free - h->object_base;
 244  register long i;
 245  long already;
 246  char *object_base;
 247
 248  /* Compute size for new chunk.  */
 249  new_size = (obj_size + length) + (obj_size >> 3) + h->alignment_mask + 100;
 250  if (new_size < h->chunk_size)
 251    new_size = h->chunk_size;
 252
 253  /* Allocate and initialize the new chunk.  */
 254  new_chunk = CALL_CHUNKFUN (h, new_size);
 255  if (!new_chunk)
 256    (*obstack_alloc_failed_handler) ();
 257  h->chunk = new_chunk;
 258  new_chunk->prev = old_chunk;
 259  new_chunk->limit = h->chunk_limit = (char *) new_chunk + new_size;
 260
 261  /* Compute an aligned object_base in the new chunk */
 262  object_base =
 263    __PTR_ALIGN ((char *) new_chunk, new_chunk->contents, h->alignment_mask);
 264
 265  /* Move the existing object to the new chunk.
 266     Word at a time is fast and is safe if the object
 267     is sufficiently aligned.  */
 268  if (h->alignment_mask + 1 >= DEFAULT_ALIGNMENT)
 269    {
 270      for (i = obj_size / sizeof (COPYING_UNIT) - 1;
 271           i >= 0; i--)
 272        ((COPYING_UNIT *)object_base)[i]
 273          = ((COPYING_UNIT *)h->object_base)[i];
 274      /* We used to copy the odd few remaining bytes as one extra COPYING_UNIT,
 275         but that can cross a page boundary on a machine
 276         which does not do strict alignment for COPYING_UNITS.  */
 277      already = obj_size / sizeof (COPYING_UNIT) * sizeof (COPYING_UNIT);
 278    }
 279  else
 280    already = 0;
 281  /* Copy remaining bytes one by one.  */
 282  for (i = already; i < obj_size; i++)
 283    object_base[i] = h->object_base[i];
 284
 285  /* If the object just copied was the only data in OLD_CHUNK,
 286     free that chunk and remove it from the chain.
 287     But not if that chunk might contain an empty object.  */
 288  if (! h->maybe_empty_object
 289      && (h->object_base
 290          == __PTR_ALIGN ((char *) old_chunk, old_chunk->contents,
 291                          h->alignment_mask)))
 292    {
 293      new_chunk->prev = old_chunk->prev;
 294      CALL_FREEFUN (h, old_chunk);
 295    }
 296
 297  h->object_base = object_base;
 298  h->next_free = h->object_base + obj_size;
 299  /* The new chunk certainly contains no empty object yet.  */
 300  h->maybe_empty_object = 0;
 301}
 302# ifdef _LIBC
 303libc_hidden_def (_obstack_newchunk)
 304# endif
 305
 306/* Return nonzero if object OBJ has been allocated from obstack H.
 307   This is here for debugging.
 308   If you use it in a program, you are probably losing.  */
 309
 310/* Suppress -Wmissing-prototypes warning.  We don't want to declare this in
 311   obstack.h because it is just for debugging.  */
 312int _obstack_allocated_p (struct obstack *h, void *obj);
 313
 314int
 315_obstack_allocated_p (struct obstack *h, void *obj)
 316{
 317  register struct _obstack_chunk *lp;   /* below addr of any objects in this chunk */
 318  register struct _obstack_chunk *plp;  /* point to previous chunk if any */
 319
 320  lp = (h)->chunk;
 321  /* We use >= rather than > since the object cannot be exactly at
 322     the beginning of the chunk but might be an empty object exactly
 323     at the end of an adjacent chunk.  */
 324  while (lp != NULL && ((void *) lp >= obj || (void *) (lp)->limit < obj))
 325    {
 326      plp = lp->prev;
 327      lp = plp;
 328    }
 329  return lp != NULL;
 330}
 331\f
 332/* Free objects in obstack H, including OBJ and everything allocate
 333   more recently than OBJ.  If OBJ is zero, free everything in H.  */
 334
 335# undef obstack_free
 336
 337void
 338obstack_free (struct obstack *h, void *obj)
 339{
 340  register struct _obstack_chunk *lp;   /* below addr of any objects in this chunk */
 341  register struct _obstack_chunk *plp;  /* point to previous chunk if any */
 342
 343  lp = h->chunk;
 344  /* We use >= because there cannot be an object at the beginning of a chunk.
 345     But there can be an empty object at that address
 346     at the end of another chunk.  */
 347  while (lp != NULL && ((void *) lp >= obj || (void *) (lp)->limit < obj))
 348    {
 349      plp = lp->prev;
 350      CALL_FREEFUN (h, lp);
 351      lp = plp;
 352      /* If we switch chunks, we can't tell whether the new current
 353         chunk contains an empty object, so assume that it may.  */
 354      h->maybe_empty_object = 1;
 355    }
 356  if (lp)
 357    {
 358      h->object_base = h->next_free = (char *) (obj);
 359      h->chunk_limit = lp->limit;
 360      h->chunk = lp;
 361    }
 362  else if (obj != NULL)
 363    /* obj is not in any of the chunks! */
 364    abort ();
 365}
 366
 367# ifdef _LIBC
 368/* Older versions of libc used a function _obstack_free intended to be
 369   called by non-GCC compilers.  */
 370strong_alias (obstack_free, _obstack_free)
 371# endif
 372\f
 373int
 374_obstack_memory_used (struct obstack *h)
 375{
 376  register struct _obstack_chunk* lp;
 377  register int nbytes = 0;
 378
 379  for (lp = h->chunk; lp != NULL; lp = lp->prev)
 380    {
 381      nbytes += lp->limit - (char *) lp;
 382    }
 383  return nbytes;
 384}
 385\f
 386# ifdef _LIBC
 387#  include <libio/iolibio.h>
 388# endif
 389
 390# ifndef __attribute__
 391/* This feature is available in gcc versions 2.5 and later.  */
 392#  if __GNUC__ < 2 || (__GNUC__ == 2 && __GNUC_MINOR__ < 5)
 393#   define __attribute__(Spec) /* empty */
 394#  endif
 395# endif
 396
 397static void
 398print_and_abort (void)
 399{
 400  /* Don't change any of these strings.  Yes, it would be possible to add
 401     the newline to the string and use fputs or so.  But this must not
 402     happen because the "memory exhausted" message appears in other places
 403     like this and the translation should be reused instead of creating
 404     a very similar string which requires a separate translation.  */
 405# ifdef _LIBC
 406  (void) __fxprintf (NULL, "%s\n", _("memory exhausted"));
 407# else
 408  fprintf (stderr, "%s\n", _("memory exhausted"));
 409# endif
 410  exit (1);
 411}
 412
 413#endif  /* !ELIDE_CODE */