exec_cmd.hon commit Why does it mean we do not have to register shallow if we have one? (fcd1e31)
   1#ifndef __GIT_EXEC_CMD_H_
   2#define __GIT_EXEC_CMD_H_
   3
   4extern void git_set_exec_path(const char *exec_path);
   5extern const char* git_exec_path(void);
   6extern int execv_git_cmd(const char **argv); /* NULL terminated */
   7extern int execl_git_cmd(const char *cmd, ...);
   8
   9
  10#endif /* __GIT_EXEC_CMD_H_ */