cmd_diff(): make it obvious which cases are exclusive of each other

At first glance the OBJ_COMMIT, OBJ_TREE, and OBJ_BLOB cases look like
they might be mutually exclusive.  But the OBJ_COMMIT case doesn't end
the loop iteration with "continue" like the other two cases, but
rather falls through.  So use if...else if...else construct to make it
more obvious that only the last two cases are mutually exclusive.

Signed-off-by: Michael Haggerty <mhagger@alum.mit.edu>
Signed-off-by: Junio C Hamano <gitster@pobox.com>

diff --git a/builtin/diff.c b/builtin/diff.c
index 84243d99568c57c03b1179f7282d9883a04d35cb..9fc273d8cd78d53a55047e17d44eb89291741167 100644 (file)
--- a/builtin/diff.c
+++ b/builtin/diff.c
@@ -350,22 +350,21 @@ int cmd_diff(int argc, const char **argv, const char *prefix)
                        die(_("invalid object '%s' given."), name);
                if (obj->type == OBJ_COMMIT)
                        obj = &((struct commit *)obj)->tree->object;
+
                if (obj->type == OBJ_TREE) {
                        obj->flags |= flags;
                        add_object_array(obj, name, &ent);
-                       continue;
-               }
-               if (obj->type == OBJ_BLOB) {
+               } else if (obj->type == OBJ_BLOB) {
                        if (2 <= blobs)
                                die(_("more than two blobs given: '%s'"), name);
                        hashcpy(blob[blobs].sha1, obj->sha1);
                        blob[blobs].name = name;
                        blob[blobs].mode = entry->mode;
                        blobs++;
-                       continue;
 
+               } else {
+                       die(_("unhandled object '%s' given."), name);
                }
-               die(_("unhandled object '%s' given."), name);
        }
        if (rev.prune_data.nr) {
                if (!path)