Given the pattern "1/2/3/4" and the path "1/2/3/4/f", the pattern
prefix is "1/2/3/4". We will compare and remove the prefix from both
pattern and path and come to this code
/*
* If the whole pattern did not have a wildcard,
* then our prefix match is all we need; we
* do not need to call fnmatch at all.
*/
if (!patternlen && !namelen)
return 1;
where patternlen is zero (full pattern consumed) and the remaining
path in "name" is "/f". We fail to realize it's matched in this case
and fall back to fnmatch(), which also fails to catch it. Fix it.
Signed-off-by: Nguyễn Thái Ngọc Duy <pclouds@gmail.com> Signed-off-by: Junio C Hamano <gitster@pobox.com>