If do_one_ref() is called recursively, then the inner call should not
permanently overwrite the value stored in current_ref by the outer
call. Aside from the tiny optimization loss, peel_ref() expects the
value of current_ref not to change across a call to peel_entry(). But
in the presence of replace references that assumption could be
violated by a recursive call to do_one_ref:
The inner call to do_one_ref() was unconditionally setting current_ref
to NULL when it was done, causing peel_ref() to perform an invalid
memory access.
So change do_one_ref() to save the old value of current_ref before
overwriting it, and restore the old value afterward rather than
setting it to NULL.
Reported-by: Mantas Mikulėnas <grawity@gmail.com> Signed-off-by: Michael Haggerty <mhagger@alum.mit.edu> Signed-off-by: Junio C Hamano <gitster@pobox.com>