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re
modulus function
author
Andrew Lorimer
<andrew@lorimer.id.au>
Mon, 3 Dec 2018 21:54:49 +0000
(08:54 +1100)
committer
Andrew Lorimer
<andrew@lorimer.id.au>
Mon, 3 Dec 2018 21:54:49 +0000
(08:54 +1100)
spec/prelim.md
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b/spec/prelim.md
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spec/prelim.md
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spec/prelim.md
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-63,3
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$${(x-h)^2 \over a^2} - {(y-k)^2 \over b^2} = 1$$
${(x-h)^2 \over a^2} - {(y-k)^2 \over b^2} = 1$ and ${(y-k)^2 \over b^2} - {(x-h)^2 \over a^2} = 1$ are **conjugate hyperbolas**
${(x-h)^2 \over a^2} - {(y-k)^2 \over b^2} = 1$ and ${(y-k)^2 \over b^2} - {(x-h)^2 \over a^2} = 1$ are **conjugate hyperbolas**
+## Modulus function
+
+$$|x|=\sqrt{x^2}$$
\ No newline at end of file