- {\centering \begin{tabular}{ l r } % TODO need to fix centering here
- \hline & no \\ \hline
- $v=u+at$ & $x$ \\
- $s = {1 \over 2}(v+u)t$ & $a$ \\
- $s=ut+{1 \over 2}at^2$ & $v$ \\
- $s=vt-{1 \over 2}at^2$ & $u$ \\
- $v^2=u^2+2as$ & $t$ \\ \hline
- \end{tabular}}
-
- \[ v_{\text{avg}} = \frac{\Delta\text{position}}{\Delta t} \]
- \begin{align*}
- \text{speed} &= |{\text{velocity}}| \\
- &= \sqrt{v_x^2 + v_y^2 + v_z^2}
- \end{align*}
- \textbf{Distance travelled between \(t=a \rightarrow t=b\):}
- \[= \int^b_a \sqrt{\left(\frac{dx}{dt}\right)^2 + \left(\frac{dy}{dt}\right)^2} \cdot dt \]
+
+ \begin{center}
+ \renewcommand{\arraystretch}{1}
+ \begin{tabular}{ l r } % TODO need to fix centering here
+ \hline & no \\ \hline
+ \(v=u+at\) & \(x\) \\
+ \(v^2 = u^2+2as\) & \(t\) \\
+ \(s = \frac{1}{2} (v+u)t\) & \(a\) \\
+ \(s = ut + \frac{1}{2} at^2\) & \(v\) \\
+ \(s = vt- \frac{1}{2} at^2\) & \(u\) \\ \hline
+ \end{tabular}
+ \end{center}
+
+ \[ v_{\text{avg}} = \frac{\Delta\text{position}}{\Delta t} \]
+ \begin{align*}
+ \text{speed} &= |{\text{velocity}}| \\
+ &= \sqrt{v_x^2 + v_y^2 + v_z^2}
+ \end{align*}
+
+ \textbf{Distance travelled between \(t=a \rightarrow t=b\):}
+ \[= \int^b_a \sqrt{\left(\frac{dx}{dt}\right)^2 + \left(\frac{dy}{dt}\right)^2} \cdot dt \]