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clarify calculus notes
author
Andrew Lorimer
<andrew@lorimer.id.au>
Sun, 19 Aug 2018 10:41:33 +0000
(20:41 +1000)
committer
Andrew Lorimer
<andrew@lorimer.id.au>
Sun, 19 Aug 2018 10:41:33 +0000
(20:41 +1000)
spec/calculus.md
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diff --git
a/spec/calculus.md
b/spec/calculus.md
index 2b68bf5692bec02045cdccc1b1d81146c69ecd72..3823f37d7dbfc72d5eb0596b20a963276bb03c39 100644
(file)
--- a/
spec/calculus.md
+++ b/
spec/calculus.md
@@
-145,11
+145,11
@@
$\log_b y^{x^n} = x^n \log_b y$
### $e$ as a logarithm
-$$\
log_e e = 1
$$
+$$\
operatorname{if} y=e^x, \quad \operatorname{then} x=\log_e y
$$
$$\ln x = \log_e x$$
### Differentiating logarithms
-$${d
\over dx} \log_b x = {1 \over x \ln b
}$$
+$${d
(\log_e x)\over dx} = x^-1 = {1 \over x
}$$
## Solving $e^x$