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[spec] add formula for length of a parametric curve
author
Andrew Lorimer
<andrew@lorimer.id.au>
Sun, 19 May 2019 04:15:04 +0000
(14:15 +1000)
committer
Andrew Lorimer
<andrew@lorimer.id.au>
Sun, 19 May 2019 04:15:04 +0000
(14:15 +1000)
spec/calculus.md
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diff --git
a/spec/calculus.md
b/spec/calculus.md
index 30a295788bca6e503648f0a6a247a7cbd3957882..43cf752fc9da76c5fece553dbecaeed0be5d433f 100644
(file)
--- a/
spec/calculus.md
+++ b/
spec/calculus.md
@@
-347,13
+347,11
@@
where $f(x) > g(x)$
## Length of a curve
## Length of a curve
-$$L = \int^b_a \sqrt{1 + ({dy \over dx})^2} \> dx$$
+$$L = \int^b_a \sqrt{1 + ({dy \over dx})^2} \> dx
\quad \text{(Cartesian)}
$$
-Evaluate on CAS. Or use Interactive $\rightarrow$ Calculation $\rightarrow$ Line $\rightarrow$ `arcLen`.
-
-### Parametric curve
+$$L = \int^b_a \sqrt{{dx \over dt} + ({dy \over dt})^2} \> dt \quad \text{(parametric)}$$
-$$l = \int^b_a \sqrt{({dx \over dt})^2 + ({dy \over dt})^2} \> dt$$
+Evaluate on CAS. Or use Interactive $\rightarrow$ Calculation $\rightarrow$ Line $\rightarrow$ `arcLen`.
## Rates
## Rates
@@
-361,7
+359,7
@@
$$l = \int^b_a \sqrt{({dx \over dt})^2 + ({dy \over dt})^2} \> dt$$
$${da \over db} \quad \text{(change in } a \text{ with respect to } b)$$
$${da \over db} \quad \text{(change in } a \text{ with respect to } b)$$
-###
#
Gradient at a point on parametric curve
+### Gradient at a point on parametric curve
$${dy \over dx} = {{dy \over dt} \div {dx \over dt}} \> \vert \> {dx \over dt} \ne 0$$
$${dy \over dx} = {{dy \over dt} \div {dx \over dt}} \> \vert \> {dx \over dt} \ne 0$$